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geodma_2:features [2017/02/15 13:57]
raian [Landscape-based features]
geodma_2:features [2017/02/15 15:03]
raian [Landscape-based features]
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 | c_PSSD | PSSD stands for Patch Size Standard Deviation, which is the root mean squared error (deviation from the mean) in patch size. This is the population standard deviation, not the sample standard deviation. | $PSSD = \sqrt{\frac{\sum_{j=1}^n \left(a_j - MPS \right)^2}{n}} 10^{-4}$ | $\geq 0$| $ha$ | | c_PSSD | PSSD stands for Patch Size Standard Deviation, which is the root mean squared error (deviation from the mean) in patch size. This is the population standard deviation, not the sample standard deviation. | $PSSD = \sqrt{\frac{\sum_{j=1}^n \left(a_j - MPS \right)^2}{n}} 10^{-4}$ | $\geq 0$| $ha$ |
 | c_LSI | LSI stands for Landscape Shape Index, which is equals the sum of the landscape boundary and all edge segments ($m$) within the boundary. This sum involves the corresponding patch type (including borders), divided by the two times the square root of the total landscape area ($m^2$) multiplied by pi ($\pi$). | $LSI = \frac{\sum_{j=1}^n e_j}{2\sqrt{\pi \times A}}$ | $\geq 1$| - | | c_LSI | LSI stands for Landscape Shape Index, which is equals the sum of the landscape boundary and all edge segments ($m$) within the boundary. This sum involves the corresponding patch type (including borders), divided by the two times the square root of the total landscape area ($m^2$) multiplied by pi ($\pi$). | $LSI = \frac{\sum_{j=1}^n e_j}{2\sqrt{\pi \times A}}$ | $\geq 1$| - |
-| c_MSI | MSI stands for Mean Shape Index, which is equals the sum of the patch perimeter ($m$) divided ​by the square root of patch area ($m^2$) for each patch of the corresponding patch type. | $\frac{\sum_{j=1}^n \frac{p_j}{2 \times \sqrt{\pi \times a_j}}}{n}$| $\geq 1$| - | +| c_MSI | MSI stands for Mean Shape Index, which is equals the sum of the patch perimeter ($m$) by divided two times the square root of patch area ($m^2$) multiplied by pi ($\pi$) for each patch of the corresponding patch type, divided by the the number of patches of the same patch type (class). | $MSI = \frac{\sum_{j=1}^n \frac{p_j}{2 \times \sqrt{\pi \times a_j}}}{n}$| $\geq 1$| - | 
-| c_AWMSI | Area-Weighted MSI equals the sum, across all patches ​of the corresponding patch type, of each patch perimeter ​($m$) divided by the square root of patch area ($m^2$). | $\sum_{j=1}^n \left[ \frac{p_j}{2 \sqrt{\pi \times a_j}} \times \frac{a_j}{\sum_{j=1}^n a_j} \right]$| $\geq 1$| - | +| c_AWMSI | AWMSI stands for Area-Weighted MSI, which is equals the sum of the landscape boundary and all edge segments ​($m$) within the boundary. This sum involves the corresponding patch type (including borders), ​divided by the two times the square root of the total landscape ​area ($m^2$) multiplied by pi ($\pi$). This first term is multiplied by the area of the corresponding patch, divided by the sum of the areas of all patches of the same patch type (class).| $AWMSI = \sum_{j=1}^n \left[ \frac{p_j}{2 \sqrt{\pi \times a_j}} \times \frac{a_j}{\sum_{j=1}^n a_j} \right]$| $\geq 1$| - | 
-| c_MPFD | MPFD stands for the Mean Patch Fractal Dimension. | $\frac{\sum_{j=1}^{n} \frac{2 \times \ln{p_j}}{\ln{a_j}}}{N}$ | | |+| c_MPFD | MPFD stands for the Mean Patch Fractal Dimension. | $MPFD = \frac{\sum_{j=1}^{n} \frac{2 \times \ln{p_j}}{\ln{a_j}}}{N}$ | | |
 | c_AWMPFD| AWMPFD stands for Area-weighted Mean Patch Fractal Dimension. | $\sum_{j = 1}^{n} [\frac{2 \times \ln{p_j}}{\ln{a_j}} \times \frac{a_j}{\sum_{j = 1}^{n} a_{ij}}}]$ | | | | c_AWMPFD| AWMPFD stands for Area-weighted Mean Patch Fractal Dimension. | $\sum_{j = 1}^{n} [\frac{2 \times \ln{p_j}}{\ln{a_j}} \times \frac{a_j}{\sum_{j = 1}^{n} a_{ij}}}]$ | | |
 | c_ED | Edge Density equals the sum of the lengths ($m$) of all edge segments involving the corresponding patch type, divided by the total landscape area ($m^2$). | $\frac{\sum_{j=1}^m e_j}{A} 10^{4}$| $\geq 0$| $m/ha$ | | c_ED | Edge Density equals the sum of the lengths ($m$) of all edge segments involving the corresponding patch type, divided by the total landscape area ($m^2$). | $\frac{\sum_{j=1}^m e_j}{A} 10^{4}$| $\geq 0$| $m/ha$ |

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